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Fizz Buzz Problem by Python

2019/9/23.  Fizz Buzz Problem by Python

Source codes

for i in range(1, 21):
    if i % 15 == 0:
        print("Fizz Buzz")
        continue
    if i % 3 == 0:
        print("Fizz")
        continue
    if i % 5 == 0:
        print("Buzz")
        continue
    print(i)

This is the source code of Fizz Buzz Problem by Python.
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